Is any composite Fermat number divisible by the factor $5h2ⁿ+1$?

Rok, strany: 1997, 17 - 21

We establish a sufficient condition which shows when a composite Fermat number $F_m=2^2m+1$ is divisible by $5h2^m+2+1$. We also prove that if $5· 2ⁿ+1|F_m$ then $n$ is an odd number. An interesting open problem is introduced.

ISO 690:

Křížek, M., Chleboun, J. 1997. Is any composite Fermat number divisible by the factor $5h2ⁿ+1$?. In Tatra Mountains Mathematical Publications, vol. 11, no.2, pp. 17-21. 1210-3195.

APA:

Křížek, M., Chleboun, J. (1997). Is any composite Fermat number divisible by the factor $5h2ⁿ+1$?. Tatra Mountains Mathematical Publications, 11(2), 17-21. 1210-3195.