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Every set is ``symmetric'' for some function

In: Mathematica Slovaca, vol. 63, no. 4
Andrzej Nowik - Marcin Szyszkowski

Details:

Year, pages: 2013, 897 - 901
Keywords:
symmetrically continuous functions
About article:
Let $\langle hn\rangle$ denote a sequence of positive real numbers. We show that for every set $A \subseteq \mathbb{R}$ there exists a function $f:\mathbb{R}\toω$ such that $A = \{x\in\mathbb{R}: (\exists \langle hn\rangle) [hn \searrow 0 & (\forall n\in\mathbb{N})(f(x - hn)= f(x + hn) = f(x))]\}$. This solves a problem of K. Ciesielski, K. Muthuvel and A. Nowik.
How to cite:
ISO 690:
Nowik, A., Szyszkowski, M. 2013. Every set is ``symmetric'' for some function. In Mathematica Slovaca, vol. 63, no.4, pp. 897-901. 0139-9918. DOI: https://doi.org/10.2478/s12175-013-0143-0

APA:
Nowik, A., Szyszkowski, M. (2013). Every set is ``symmetric'' for some function. Mathematica Slovaca, 63(4), 897-901. 0139-9918. DOI: https://doi.org/10.2478/s12175-013-0143-0
About edition: